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0.1g of carbon dioxide occupies a volume...

0.1g of carbon dioxide occupies a volume of 320cc at certain conditions. Under similar conditions 0.2g of 3 dioxide of element 'X' occupies 440cc. Calculate the atomic weight of 'X'.

Text Solution

Verified by Experts

Applying Avogadro.s law,` (n_(1))/(n_(2)) = (V_(1))/(V_(2))`
But number of moles ` =n = w//M`
`(V_(1))/(V_(2)) = (w_(1)M_(2))/(w_(2)M_(1))`
Molecular weight of dioxide of X ` = M_(2) = (V_(1))/(V_(2)) xx (w_(2)m_(1))/(w_(1)) = (320)/(440) xx (0.2)/(0.1) xx 44 = 64`
Molecular weight of `XO_(2) = 64`
Therefore, atomic weight of X = 32
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