A vessel of irregular shape has a volume 'V'. It is first evacuated and coupled with a vessel of 4L capacity at `35^@C` and 10 atm pressure. If the final pressure in both the vessels is 3atm, calculate the volume V.

Explanation

Unknown vessel Known vessel
`V_(1) = VL " "V_(2) = 4L`
`P_(1) = 0 "atm " P_(2) = 10` atm
The average pressure (P) of the mixture of the gases from two vessels ` = P = (P_(1)V_(1) + P_(2)V_(2))/(V_(1) + V_(2))`
` 3 = (0 xx V + 10 xx 4)/(V + 4) = (40)/(V + 4)`
Solving, V = 9.3 L
The volume of the given vessel of irregular shape is 9.3 L