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720cc of methane diffused through a poro...

720cc of methane diffused through a porous membrane in 30min. Under identical conditions 240cc of gas 'X'diffused in 20 min. Calculate the molecular weight of 'X'.

Text Solution

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Rate of diffusion of methane ` = 720//30 = 24 "cc" m^(-1)`
Rate of diffusion of gas .X. `240//20 = 12 "cc" m^(-1)`
Ratio of rates of diffusion is given as `(r_(1))/(r_(2)) = sqrt((M_(2))/(M_(1))) = (24)/(12) = 12`
Molecular weight of .X. ` = 2^(2) xx 16 = 64`
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