Home
Class 11
CHEMISTRY
One litre of hydrogen effused in 8min th...

One litre of hydrogen effused in 8min through a 8 fine aperture. What is the time required for the same volume of ozone to effuse under similar conditions?

Text Solution

Verified by Experts

The ratio of times taken for some volume of two gases, under similar conditions is given by Graham.s equation
`(t_(2))/(t_(1)) = sqrt((M_(2))/(M_(1))) or t_(2) = t_(1) sqrt((M_(2))/(M_(1)))`
Time required for ozone to effuse ` = 8 xx sqrt(48//2) = 39.2` min.
Promotional Banner

Similar Questions

Explore conceptually related problems

If 500cm^3 of hydrogen diffused in 16 minutes through a fine hole, how much time does the same volume of ozone (O_3) take for diffusion?

200cc of ozone diffused in 15 min through a porous membrane. How much time does 150cc of oxygen take to difffuse, under similar conditions ?

A certain volume of Methane diffuses in 10 Sec through a porous partition. The time taken by an equal volume of oxygen to diffuse under the same condition is

What is the volume ratio of equal masses of hydrogen,methane and oxygen present under similar conditions?

X ml of H_2 gas effuses through a hole in a container in 5 sec. The time taken for the effusion of same volume of gas specified below under identical conditions is

One L ammonia diffuses through a fine hole in 32.5 sec. How much time will 0.6 L of nitrogen takes to diffuse under similar conditions ?

Certain volume of oxygen gas undergoes effusion in 15 min. Under similar conditions, what is the time required for the effusion of same volume of chlorine gas?

One Litre each of sulphurdioxide and ozone are allowed to react. Find the limiting reagent.What volume of sulphurtrioxide is formed under similar conditions?

At 27^@ C, 500 mL of helium diffuses in 30 min. What is the time (in hours) taken for 1000 mL of SO_(2) to diffuse under same experimental conditions ?