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For nitrogen a = 1.4 L^(2) atm, mol^(-2)...

For nitrogen a = 1.4 `L^(2) atm, `mol^(-2)`, b = 0.04 L `mol^(-1)`. Find out the diameter of nitrogen molecule.

Text Solution

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`b = 4 xx (4)/(3) pir^(3) xx N`
b = 0.04 L `mol^(-1) = 40 "cc" mol^(-1)`
`40 = 4 xx (4)/(3) xx (22)/(7) xx r^(3) xx 6.023 xx 10^(23)`
`r^(3) = 4 xx 10^(-24)` cm , `r = 1.58 A^(@)`
Diameter of nitrogen molecule ` = 1.58 xx2 = 3.16 A^(@)`
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