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The ratio of rates of diffusion of two g...

The ratio of rates of diffusion of two gases x and y under similar conditions is 2:1. What will be the ratio of their average speeds if gas X is at `-23^@C` and gas y is at `273^@C`?

Text Solution

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Ratio of rates of diffusion ` (r_(x))/(r_(y)) = sqrt((M_(y))/(M_(x))) = 2 (or) (M_(y))/(M_(x)) = 4`
Ratio of average speeds is given as, ` (barC_(X))/(C_(y)) = sqrt((T_(X))/(T_(y))(M_(y))/(M_(x)))`
substituting the values, the ratio of speeds ` = sqrt((250)/(500 xx 4) = sqrt(2) : 1 = 1.414 : 1 (or) 1 : 707`
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