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At 25^@ C, the dissociation constant of ...

At `25^@ C`, the dissociation constant of `NH_4 OH` is `2 xx 10^(-5)`. If the molar concentration of `NH_2 OH` is `0.2 M`, calculate the proton concentration of aqueous ammonia solution.

Text Solution

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`K_b=` Dissociation constant of base `= 2 xx 10^(-5) C = `Concentration of base `= 2 xx 10^(-1)`
`[OH^(-) ]= sqrt(K_b C) =sqrt(2 xx 10^(-5) xx 2 xx 10^(-1) ) = 2 xx 10^(-3) M`
`[H^(+) ]=K_(w) // [OH^(-) = 1 xx 10^(-14) // 2 xx 10^(-3) = 5xx 10^(-12) M`
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