The no.of `H_(3),O^(+)` ions present in 10 ml of water at `25^(@)`C is

Explanation

For pure water at `25^@ C, [H^(+)] = [H_(3) O^(+)] = 1 xx 10^(-7) mol L^(-1)`
1000 ml of water has `10^(-7)` mole of `H_(3) O^(+)`
`[H_3 O^(+) ]` in 10 ml of water `= (10^(-7) xx 10)/(1000 )= 10^(-9) ` mole
But one mole of `H_3 O^(+) = 6 xx 10^(23) H^(+)` ions
Numbers of `H_3 O^(+)` ions present in ten ml water `= 10 xx 6 xx 10^(23) = 6 xx 10^(14)` ions