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Calculate the dissociation constant of w...

Calculate the dissociation constant of water at room temperature

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Dissociation of water is given as, `H_2 O hArr H^(+) _OH^(-)`
Dissociation constant `K_a` is given as `K_a ([H^(+)][OH^(-)])/([H_2 O]) = (k_w )/( [H_2O]) =(1xx 10^(-14))/( 55.5 )`
Dissociation constant of acid `= 1.8 xx10^(-16) mol L^(-1)`
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