The `P^(H)` of `10^(-8)` M HCI is

Explanation

for a solution of known `[H^(+)]`, the pH value is given as, pH = -log[`H^+`]
If `[H^+]` is `10^(-8)` pH value is `- log (10^(-8)) = 8`.
`10^(-8) ` M HCl solution is acidic, even though it is a very dilute solution.
It.s` [H^(+)] gt 10^(-7)`M. Therefore pH is less than 7, but close to 7 due yo its dilute nature.