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The pH of 0.08 M HOCI is 2.85. Calculate...

The pH of 0.08 M HOCI is 2.85. Calculate the degree of dissociation.

Text Solution

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Given value of `pH=2.85, [H^+] = 1.4 xx 10^(-3) mol L^(-1)`
`[H^(+)] =C alpha , 1.4 xx 10^(-3) = 0.008 xx alpha , alpha = 1.75 xx 10^(-2)`
The degree of dissociation, `alpha =1.77 xx 10^(-2)`.
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