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Calculate the pH of 0.001 Maniline. What...

Calculate the pH of 0.001 Maniline. What is the ionisation constant of anilinium cation? `(K_b = 3.5 xx 10^(-10))`

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`[OH^(-) ]=sqrt(K_b C ) = sqrt( 3.5 xx 10^(-10 ) xx 10^(-3)) = 6 xx 10^(-7) mol L^(-1)`
`pOH = -log 6 xx 10^(-7) = 7-log 6`
pH = 14 - 7 + log 6 = 7.78
Ionisation constant of anilinium cation is the ratio of `K_w and K_b`
`k_a = (K_w)/(k_b) = ( 1 xx 10^(-14) )/(3.5 xx 10^(-10)) = 2.86 xx 10^(-5)`
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