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What is the minimum volume of water requ...

What is the minimum volume of water required to dissove `1g` of calcium sulphate at `298K` ? (For calcium sulphate, `K_(sp)` is `9.1xx10^(-6)`).

Text Solution

Verified by Experts

Solubility product of calcium sulphate, `K_(sp)` for `CaSO_4 = 9.1 xx 10^(-6)`
Solubility of `CaSO_4= sqrt(K_(sp)) = 3.016 xx 10^(-3) mol L^(-1)`
Solubility of `CaSO_4 = 3.016 xx 10^(-3)xx 136 = 0.41 g L^(-1)`
0.41 gram of `CaSO_4` is dissolved in a solution of volume one litre.
Volume of solution in which 1 gram of `CaSO_4` is dissolved
`=" weight " xx (1)/("solubility ")=1 xx (1)/(0.41 ) = 2.441` .
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