If the solubility of zirconium phosphate is x, what is its solubility product? What are the units of solubility product of `Zr_3 (PO_4 )_4`?

Explanation

Zirconium phosphate dissociates in aqueous solutions as `Zr_3 (PO_4)_4 hArr +3Zr^(4+) + 4PO_(4)^(3-)`
If x is the solubility, `[Zr^(4+)] =3s and [PO_(4)^(3-) ] = 4s`
The solubility product `K_(sp)` is `Kp_(sp) = [Zr^(4+)] [PO_(4)^(3-) ]^4 =(3s)^2 (4s)^4 = 6912 s^7`
The units of solubility product are : `mol^7 L^(-7)`