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Calculate the pH of 0.001 M aqueous solu...

Calculate the pH of 0.001 M aqueous solution of `ZnCl_2, K_a` for the equilibrium,
` Zn^(2+) +H_(2) O hArr Zn (OH)^(+) +H^(+) ` is ` 1 xx 10^(-9)`

Text Solution

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`[H^(+)] = c xx h = c sqrt(K_H // C)= sqrt(K_H xxC ) = sqrt(10^(-9) xx 0.001 ) = 10^(-6)`
`pH =- log [10^(-6) ]=6`
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