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2H2 O hArr H(3)O^(+) + OH^(-) The ioni...

`2H_2 O hArr H_(3)O^(+) + OH^(-)` The ionic product changes from `10^(-14)` at `25^@ C` to `9.62 xx 10^(-14)` at `60^@` C. What is the pOH of water at `60^@` C ?

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