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Find energy of photons which corresponds to light of frequency `3 xx 10^(12) Hz`

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Calculate the energy of one mole of photons of radiations whose frequency is 3 xx 10^(12) Hz

Calculate energy of one mole of photons of radiation whose frequency is 5xx10^(14) Hz.

Knowledge Check

  • When a certain metal was irradiated with light of frequency 3.2 xx 10^(16) Hz, the photoelectrons emitted had twice the kinetic energy as did photoelectrons when the same metal was irradiated with light of frequency 2.0 xx 10^(16) Hz . The threshold frequency for the metal is

    A
    `1.2 xx 10^(16) Hz`
    B
    `8s xx 10^(15) Hz`
    C
    `8 xx 10^(16) Hz`
    D
    `1.2 xx 10^(15) Hz`

  • When a certain metal was irradiated with light of frequency 40xx10^(16) s^(-1) , the photoelectrons emitted had four times kinetic energy as the kinetic energy of photoelectrons emitted when the same metal was irradiated with light of frequency 2.0 xx 10^(16) s^(-1) . the trhreshold frequency ( v_(0) ) of the metal in s^(-1) is

    A
    `2xx10^(16)`
    B
    `4 xx 10^(16)`
    C
    `2.5 xx 10^(16)`
    D
    `1.33 xx 10^(16)`

  • A light of frequency 1.6xx10^(16) Hz when falls on a metal plate emits electrons that have double the kinetic energy compared to the kinetic energy of emitted electrons when frequency of 1.0xx10^(16) Hz falls on the same plate. The threshold frequency (lamda_(0)) of the metal in Hz is

    A
    `1xx10^(15)`
    B
    `4xx10^(15)`
    C
    `3xx10^(15)`
    D
    `4xx10^(13)`

    • Similar Questions

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    Calculate energy of one mole of photons of radiation whose frequency is 5xx10^(14)Hz .

    The threshold frequency (v_(0)) for a metal is 5 xx 10^(14)S^(-1) . Calculate the kinetic energy of emitted electron when a radiation with frequency of 2 xx 10^(15) sec^(-1) hits the metal surface.

    The work function of caesium metal is 2.14 eV . When light of frequency 6xx 10^(14) Hz is incident on the metal surface , photomission of electrons occurs . What is the maximum kinetic energy of the emitted electrons

    The work function of caesium metal is 2.14 eV . When light of frequency 6xx 10^(14) Hz is incident on the metal surface , photomission of electrons occurs . What is the stopping potential and

    The work function of caesium metal is 2.14 eV . When light of frequency 6xx 10^(14) Hz is incident on the metal surface , photomission of electrons occurs . What is the maximum speed of the emitted photoelectrons ?

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