FAOR: Dynamics (torgue equation about hinge) | Conservation of energy | FAOR problems: hinged rod | Hinge force calculation | Fixed pulley

In previous problem, what is the reaction force on the hinge ?

Two particle of mass m each are fixed to a massless rod of length 2l . The rod is hinged at one end about a smooth hinge and it performs oscillations of small angle in vertical plane. The length of the equivalent simple pendulum is:

When a body is hinged at a point and a force is acting on the body in such a way that the line of action of force is at some distance from the hinged point, the body will start rotating about the hinged point. The angular acceleration of the body can be calculated by finding the torque of that force about the hinged point. A disc of mass m and radius R is hinged at point A at its bottom and is free to rotate in the vertical plane. A force of magnitude F is acting on the ring at top most point. Component of reaction at the hinge in the horizontal direction is

When a body is hinged at a point and a force is acting on the body in such a way that the line of action of force is at some distance from the hinged point, the body will start rotating about the hinged point. The angular acceleration of the body can be calculated by finding the torque of that force about the hinged point. A disc of mass m and radius R is hinged at point A at its bottom and is free to rotate in the vertical plane. A force of magnitude F is acting on the ring at top most point. Component of reaction at the hinge in the vertical direction is

Angular momentum of a particle | Angular momentum of a rigid body in pure translation | FAOR | GRBM-General Rigid Body Motion | Torgue and angular momentum relation | Application of conservation of angular momentum | Rod particle collisions

When a body is hinged at a point and a force is acting on the body in such a way that the line of action of force is at some distance from the hinged point, the body will start rotating about the hinged point. The angular acceleration of the body can be calculated by finding the torque of that force about the hinged point. A disc of mass m and radius R is hinged at point A at its bottom and is free to rotate in the vertical plane. A force of magnitude F is acting on the ring at top most point. Tangential acceleration of the centre of mass is

A uniform rod mass m and length L is free to rotate about hinge O . A slight disturbance cause the rod to rotate freely about O and it strikes the ground. Horizontal force applied on rod by hinge just before the rod hits the surface is:

A uniform rod of mass M = 2 kg and length L is suspended by two smooth hinges 1 and 2 as shown in Fig. A force F = 4 N is applied downward at a distance L//4 from hinge 2 . Due to the application of force F , hinge 2 breaks. At this instant, applied force F is also removed. The rod starts to rotate downward about hinge 1 . ( g = 10 m//s^(2) ) The acceleration of the end point of the rod of small mass dm at the end point of the rod, when the rod becomes vertical is