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Ray AX is the bisector of angleBAC and r...

Ray AX is the bisector of `angleBAC` and ray AY is the bisector of `angleXAC`. If `angleBAY=60^(@)`, find `angleBAC`.

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To solve the problem step by step, we will follow the logical deductions based on the information provided in the question. ### Step-by-Step Solution: 1. **Understanding the Angles**: - Let the measure of angle \( BAC \) be \( x \). - Since ray \( AX \) is the bisector of angle \( BAC \), it divides \( BAC \) into two equal parts. Therefore, \( \angle BAX = \frac{x}{2} \) and \( \angle XAC = \frac{x}{2} \). 2. **Identifying the Second Bisector**: - Ray \( AY \) is the bisector of angle \( XAC \). Since \( \angle XAC = \frac{x}{2} \), ray \( AY \) divides this angle into two equal parts: - \( \angle XAY = \frac{1}{2} \times \frac{x}{2} = \frac{x}{4} \) - Therefore, \( \angle YAC = \frac{x}{4} \) as well. 3. **Setting Up the Equation**: - We know from the problem that \( \angle BAY = 60^\circ \). - We can express \( \angle BAY \) in terms of \( x \): \[ \angle BAY = \angle BAX + \angle XAY = \frac{x}{2} + \frac{x}{4} \] 4. **Finding a Common Denominator**: - To add \( \frac{x}{2} \) and \( \frac{x}{4} \), we need a common denominator. The least common multiple of 2 and 4 is 4: \[ \frac{x}{2} = \frac{2x}{4} \] - Now we can add: \[ \angle BAY = \frac{2x}{4} + \frac{x}{4} = \frac{3x}{4} \] 5. **Setting Up the Equation**: - Since we know \( \angle BAY = 60^\circ \), we can set up the equation: \[ \frac{3x}{4} = 60 \] 6. **Solving for \( x \)**: - To solve for \( x \), multiply both sides by 4: \[ 3x = 240 \] - Now, divide both sides by 3: \[ x = \frac{240}{3} = 80 \] 7. **Conclusion**: - Therefore, the measure of angle \( BAC \) is: \[ \angle BAC = x = 80^\circ \] ### Final Answer: \[ \angle BAC = 80^\circ \]
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NAVNEET PUBLICATION - MAHARASHTRA BOARD-LINE AND ANGLES-Skill Testing Exercise
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  12. If angleA and angleB are supplementary angles. If 4angleA=5angleB, the...

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  13. In DeltaABC,angleA:angleB:angleC=3:4:5. Find the measure of each angle...

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  14. In DeltaABC,angleA=(angleB+angleC)/(3) and angleB:angleC=2:1. Find the...

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  17. For the figure given below, prove that / ADC = / A + / B + / C

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  19. For the figure below, prove that / CBE + / ADF = / DAB + / DCB.

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  20. Prove that the sum of the angles of a quadrilateral is 360^(@) .

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