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In DeltaABC,angleA=70^(@) and angleB=60^...

In `DeltaABC,angleA=70^(@)` and `angleB=60^(@)`. Then the measure of an exterior angle of `DeltaABC` can be ............

A

`50^(@)`

B

`110^(@)`

C

`100^(@)`

D

`70^(@)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the measure of the exterior angles of triangle ABC where angle A = 70° and angle B = 60°. ### Step-by-Step Solution: 1. **Identify the Given Angles**: - Angle A = 70° - Angle B = 60° 2. **Find Angle C**: - Use the angle sum property of a triangle, which states that the sum of the interior angles of a triangle is 180°. - Therefore, we can write: \[ \text{Angle A} + \text{Angle B} + \text{Angle C} = 180° \] - Substituting the known values: \[ 70° + 60° + \text{Angle C} = 180° \] - Simplifying: \[ 130° + \text{Angle C} = 180° \] - To find Angle C, subtract 130° from both sides: \[ \text{Angle C} = 180° - 130° = 50° \] 3. **Calculate the Exterior Angles**: - The exterior angle of a triangle is equal to the sum of the two opposite interior angles. - **Exterior Angle at A**: - Opposite angles are B and C: \[ \text{Exterior Angle A} = \text{Angle B} + \text{Angle C} = 60° + 50° = 110° \] - **Exterior Angle at B**: - Opposite angles are A and C: \[ \text{Exterior Angle B} = \text{Angle A} + \text{Angle C} = 70° + 50° = 120° \] - **Exterior Angle at C**: - Opposite angles are A and B: \[ \text{Exterior Angle C} = \text{Angle A} + \text{Angle B} = 70° + 60° = 130° \] 4. **Summary of Exterior Angles**: - Exterior Angle A = 110° - Exterior Angle B = 120° - Exterior Angle C = 130° ### Conclusion: The measures of the exterior angles of triangle ABC are: - Exterior Angle A = 110° - Exterior Angle B = 120° - Exterior Angle C = 130°
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