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In cyclic quadrilateral ABCD, angle A - ...

In cyclic quadrilateral `ABCD, angle A - angle C =20^(@).` Then,`angle A=` ..........

A

`20^(@)`

B

`80^(@)`

C

`100^(@)`

D

`50^(@)`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the value of angle A in the cyclic quadrilateral ABCD, given that angle A - angle C = 20°. ### Step-by-Step Solution: 1. **Understand the Properties of Cyclic Quadrilaterals**: In a cyclic quadrilateral, the sum of the opposite angles is always 180°. Therefore, we can write the following equation: \[ \text{Angle A} + \text{Angle C} = 180° \quad \text{(Equation 1)} \] 2. **Use the Given Information**: We are given that: \[ \text{Angle A} - \text{Angle C} = 20° \quad \text{(Equation 2)} \] 3. **Add Equation 1 and Equation 2**: To eliminate angle C, we can add Equation 1 and Equation 2: \[ (\text{Angle A} + \text{Angle C}) + (\text{Angle A} - \text{Angle C}) = 180° + 20° \] This simplifies to: \[ 2 \cdot \text{Angle A} = 200° \] 4. **Solve for Angle A**: Divide both sides by 2 to find angle A: \[ \text{Angle A} = \frac{200°}{2} = 100° \] ### Final Answer: \[ \text{Angle A} = 100° \]
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