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The length, breadth and height of a hall...

The length, breadth and height of a hall are 16 m, 10 m and 6 m respectively. It has two doors measuring 2 m `times` 1.5 m each and four windows measuring 2 m `times` 2 m each. Find the cost of white washing all the four walls and the ceiling of the hall at the rate of Rs. 5 per `m^(2)`.

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To find the cost of whitewashing all the four walls and the ceiling of the hall, we will follow these steps: ### Step 1: Calculate the Surface Area of the Hall The surface area to be whitewashed includes the four walls and the ceiling. 1. **Calculate the area of the four walls:** - The formula for the area of the four walls is: \[ \text{Area of walls} = 2 \times (h \times l + h \times b) \] - Where: - \( h = 6 \, m \) (height) - \( l = 16 \, m \) (length) - \( b = 10 \, m \) (breadth) - Plugging in the values: \[ \text{Area of walls} = 2 \times (6 \times 16 + 6 \times 10) \] \[ = 2 \times (96 + 60) = 2 \times 156 = 312 \, m^2 \] 2. **Calculate the area of the ceiling:** - The area of the ceiling is simply: \[ \text{Area of ceiling} = l \times b = 16 \times 10 = 160 \, m^2 \] 3. **Total area before subtracting doors and windows:** - Total area to be whitewashed: \[ \text{Total area} = \text{Area of walls} + \text{Area of ceiling} = 312 + 160 = 472 \, m^2 \] ### Step 2: Subtract the Area of Doors and Windows 1. **Calculate the area of the doors:** - Each door measures \( 2 \, m \times 1.5 \, m \): \[ \text{Area of one door} = 2 \times 1.5 = 3 \, m^2 \] - There are 2 doors: \[ \text{Total area of doors} = 2 \times 3 = 6 \, m^2 \] 2. **Calculate the area of the windows:** - Each window measures \( 2 \, m \times 2 \, m \): \[ \text{Area of one window} = 2 \times 2 = 4 \, m^2 \] - There are 4 windows: \[ \text{Total area of windows} = 4 \times 4 = 16 \, m^2 \] 3. **Total area of doors and windows:** \[ \text{Total area of doors and windows} = 6 + 16 = 22 \, m^2 \] 4. **Net area to be whitewashed:** \[ \text{Net area} = \text{Total area} - \text{Total area of doors and windows} = 472 - 22 = 450 \, m^2 \] ### Step 3: Calculate the Cost of Whitewashing 1. **Cost per square meter:** - Given that the cost of whitewashing is Rs. 5 per \( m^2 \). 2. **Total cost:** \[ \text{Total cost} = \text{Net area} \times \text{Cost per } m^2 = 450 \times 5 = 2250 \, \text{Rs.} \] ### Final Answer The cost of whitewashing all the four walls and the ceiling of the hall is **Rs. 2250**. ---
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NAVNEET PUBLICATION - MAHARASHTRA BOARD-SURFACE AREAS AND VOLUMES-SKILL TESTING EXERCISE
  1. The edge of a cube is 6 cm. Find the area of its lateral surfaces.

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  2. The outer measurements of a cuboidal tank are length 5 m, breadth 4 m ...

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  3. The length, breadth and height of a hall are 16 m, 10 m and 6 m respec...

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  4. The edge of a cubical box is 15 cm. A cuboidal box measures 16 cm time...

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  5. For a given cylinder, the radius of the base is 7 cm and its height is...

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  6. Find the total surface area of a cylinder with radius 21 cm and height...

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  7. The curved surface area of a cylinder is 110 cm^(2) and its diameter i...

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  8. The total surface area of a closed cylinder is 528 cm^(2). If its radi...

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  9. The diameter and height of a cylindrical water tank are 2 m and 14 m r...

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  10. The radius of a cylindrical roller is 140 cm and its length is 100 cm....

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  11. The diameter of a circular plate is 28 cm and its thickness is 2.5 cm....

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  12. Find the total surface area of a cone with diameter 7 cm and slant hei...

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  13. 5 conical tents with diameter 8 m and height 3 m are to be made. How m...

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  14. The curved surface area of a cone is 628 cm^(2) and its slant height i...

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  15. The total surface area of a close cone is 176 cm^(2). If its radius is...

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  16. A conical tent with radius 5 m and slant height 14 m is to be made. Ho...

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  17. 10 conical Joker.s caps with radius 14 cm and height 48 cm are to be m...

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  18. The radius of a sphere is 7 cm. Find its surface area.

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  19. The diameter of a solid hemisphere is 7 cm. Find its total surface are...

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  20. The surface area of a sphere is 314 cm^(2). Find its diameter. (pi=3.1...

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