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The edge of a cubical box is 15 cm. A cu...

The edge of a cubical box is 15 cm. A cuboidal box measures 16 cm `times` 12 cm `times` 8 cm. Total surface area of which box is greater ? By how much ?

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To determine which box has a greater total surface area and by how much, we will calculate the total surface area of both the cubical and cuboidal boxes step by step. ### Step 1: Calculate the Total Surface Area of the Cubical Box The formula for the total surface area (TSA) of a cube is given by: \[ \text{TSA} = 6 \times \text{side}^2 \] Given that the edge of the cubical box is 15 cm, we can substitute this value into the formula: \[ \text{TSA} = 6 \times (15 \, \text{cm})^2 \] Calculating \( (15 \, \text{cm})^2 \): \[ (15 \, \text{cm})^2 = 225 \, \text{cm}^2 \] Now substituting this back into the TSA formula: \[ \text{TSA} = 6 \times 225 \, \text{cm}^2 = 1350 \, \text{cm}^2 \] ### Step 2: Calculate the Total Surface Area of the Cuboidal Box The formula for the total surface area of a cuboid is: \[ \text{TSA} = 2 \times (L \times B + B \times H + H \times L) \] Where: - Length \( L = 16 \, \text{cm} \) - Breadth \( B = 12 \, \text{cm} \) - Height \( H = 8 \, \text{cm} \) Substituting the values into the formula: \[ \text{TSA} = 2 \times (16 \times 12 + 12 \times 8 + 8 \times 16) \] Calculating each term: 1. \( 16 \times 12 = 192 \) 2. \( 12 \times 8 = 96 \) 3. \( 8 \times 16 = 128 \) Now adding these values together: \[ 192 + 96 + 128 = 416 \] Now substituting this back into the TSA formula: \[ \text{TSA} = 2 \times 416 = 832 \, \text{cm}^2 \] ### Step 3: Compare the Total Surface Areas Now we compare the total surface areas of both boxes: - TSA of Cubical Box = \( 1350 \, \text{cm}^2 \) - TSA of Cuboidal Box = \( 832 \, \text{cm}^2 \) ### Step 4: Calculate the Difference To find out by how much the total surface area of the cubical box is greater than that of the cuboidal box, we subtract the TSA of the cuboidal box from that of the cubical box: \[ \text{Difference} = 1350 \, \text{cm}^2 - 832 \, \text{cm}^2 = 518 \, \text{cm}^2 \] ### Conclusion The total surface area of the cubical box is greater than that of the cuboidal box by \( 518 \, \text{cm}^2 \). ---
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NAVNEET PUBLICATION - MAHARASHTRA BOARD-SURFACE AREAS AND VOLUMES-SKILL TESTING EXERCISE
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  7. The total surface area of a closed cylinder is 528 cm^(2). If its radi...

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  8. The diameter and height of a cylindrical water tank are 2 m and 14 m r...

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  11. Find the total surface area of a cone with diameter 7 cm and slant hei...

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  13. The curved surface area of a cone is 628 cm^(2) and its slant height i...

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  14. The total surface area of a close cone is 176 cm^(2). If its radius is...

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  15. A conical tent with radius 5 m and slant height 14 m is to be made. Ho...

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  16. 10 conical Joker.s caps with radius 14 cm and height 48 cm are to be m...

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  17. The radius of a sphere is 7 cm. Find its surface area.

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  18. The diameter of a solid hemisphere is 7 cm. Find its total surface are...

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  19. The surface area of a sphere is 314 cm^(2). Find its diameter. (pi=3.1...

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