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The volume of a hemisphere is 89""5/6cm^...

The volume of a hemisphere is `89""5/6cm^(3)`. Find its diameter.

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To find the diameter of a hemisphere given its volume, we can follow these steps: ### Step 1: Understand the formula for the volume of a hemisphere. The volume \( V \) of a hemisphere is given by the formula: \[ V = \frac{2}{3} \pi r^3 \] where \( r \) is the radius of the hemisphere. ### Step 2: Convert the mixed fraction to an improper fraction. The volume given is \( 89 \frac{5}{6} \) cm³. We need to convert this mixed fraction into an improper fraction: \[ 89 \frac{5}{6} = \frac{89 \times 6 + 5}{6} = \frac{534 + 5}{6} = \frac{539}{6} \] ### Step 3: Substitute the volume into the volume formula. Now, we substitute the volume into the formula: \[ \frac{2}{3} \pi r^3 = \frac{539}{6} \] Using \( \pi \approx \frac{22}{7} \): \[ \frac{2}{3} \times \frac{22}{7} \times r^3 = \frac{539}{6} \] ### Step 4: Simplify the equation. Multiply both sides by \( 3 \) to eliminate the fraction: \[ 2 \times \frac{22}{7} \times r^3 = \frac{539 \times 3}{6} \] Now simplify the right side: \[ \frac{539 \times 3}{6} = \frac{1617}{6} \] ### Step 5: Solve for \( r^3 \). Now, rearranging gives: \[ r^3 = \frac{1617 \times 7}{2 \times 22} \] Calculating the right side: \[ r^3 = \frac{1617 \times 7}{44} \] Now calculate \( 1617 \div 11 = 147 \) (since both 1617 and 44 are divisible by 11): \[ r^3 = \frac{147 \times 7}{4} \] Calculating \( 147 \times 7 = 1029 \): \[ r^3 = \frac{1029}{4} \] ### Step 6: Find the value of \( r \). Now, we need to take the cube root: \[ r = \sqrt[3]{\frac{1029}{4}} \] Calculating \( \frac{1029}{4} = 257.25 \): \[ r \approx 6.349 \text{ cm} \] ### Step 7: Calculate the diameter. The diameter \( d \) is given by: \[ d = 2r \approx 2 \times 6.349 \approx 12.698 \text{ cm} \] ### Final Answer: The diameter of the hemisphere is approximately \( 12.7 \) cm.
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