calculate the value of `x^2+x+1/x+1/x^2` given `x^2-3x+1=0.`

If x^2-3x+1=0 , then the value of (x^4+1/x^2) div (x^2+1) is : यदि x^2-3x+1=0 , तो (x^4+1/x^2) div (x^2+1) का मान ज्ञात करें:

If x-1/x=0 the value x^2+1/x^2 will be

If x^2-3x-1=0 , then the value of (x^2+ 8x-1)(x^3+x^(-1))^-1 is: यदि x^2-3x-1=0 है, तो (x^2+ 8x-1)(x^3+x^(-1))^-1 का मान क्या होगा ?

If x^2 - 3x + 1 = 0 , then the value of (x^6 + x^4 + x^2 + 1)/(x^3) will be

x-y relation is given by y=x^(n) calculate the value of n in the following :- (i) y=(x^(2))/(x^(2//3)) (ii) y=(x^(3//2))/(x^(1)) (iii) y=(x^(1//2))/(x^(1//2)) (iv) y=(x^(3//2))/(sqrt(x))