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What is the rice in temperature of 5 kg ...

What is the rice in temperature of 5 kg of water if it is given 84,000 J heat energy? Specific heat capacity of water`=4200 J kg ^-1^@C^-1`.

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The specific heat capacity of water is ____ cal//g^(@)C

Calculate the heat energy required to raise the temperature of 2 kg of water from 10^@C to 50^@C . Specific heat capacity of water is 4200 JKg^(-1) K^(-1)

Find the increase in mass when 1 kg of water is heated from 0^@C to 100^@C . Specific heat capacity of water = 4200 J kg^(-1) K^(-1) .

A plate of area 10 cm^2 is to be electroplated with copper (density 9000 kg m^(-3) to a thickness of 10 micrometres on both sides, using a cell of 12 V . Calculate the energy spend by the cell in the process of deposition. If this energy is used to heat 100 g of water, calculate the rise in the temperature of the water. ECE of copper = 3 xx 10^(-7) kg C^(-1) and specific heat capacity of water = 4200 J kg^(-1) K^(-1) .

Find the change in the internal energy of 2 kg of water as it heated from 0^(0)C to 4^(0)C . The specific heat capacity of water is 4200 J kg^(-1) K^(-1) and its densities at 0^(0)C and 4^(0)C are 999.9 kg m^(-3) and 1000 kg m^(-3) respectively. atmospheric pressure =10^(5) Pa.

An energy of 84000 J is required to raise the temperature of 2 kg of water from 60^@ C " to " 70^@ C . Calculate the specific heat capacity of water.

Calculate the time required to heat 20kg of water from 10^(@)C to 35^(@)C using an immersion heater 1000W Assume that 80% of the power input is used to heat the water. Specific heat capacity of water = 4200J kg^(-1)K^(-1)

A piece of ice of mass of 100g and at temperature 0^(@)C is put in 200g of water of 25^(@) How much ice will melt as the temperature of the water reaches 0^(@)C ? The specific heat capacity of water = 4200 J kg ^(-1)K^(-1) and the latent heat of ice = 3.36 xx 10^(5)J kg^(-1)

True or False: The specific heat capacity of water is 1.0 cal//g^(@)C

Indian style of cooling drinking water is to keep it in a pitcher having porous walls. Water comes to the outer surface very slowly and evaporates .Most of the energy needed for evaporation is taken from the water itself and the water is cooled down. Assume that a pitcher contains 10kg water and 0.2g of water comes out per second. Assuming no backward heat transfer from the atmosphere to the water, calculate the time in which the temperature decreases by 5^(@)C . Specific heat capacity of water = 4200J kg^(-1).^@C^(-1) and latent heat of vaporization of water = 2.27 xx 10^(6)J kg^(-1)