Normality of 10V `H_2O_2` is…………… .

Calculate normality of 10V H_2O_2 .

Calculate the normality of 10 volumes H_2O_2 .

The structure of H_2O_2 is

The strength of H_(2)O_(2) is expressed in several ways like molarity, normality,% (w/V), volume strength, etc. The strength of "10 V" means 1 volume of H_(2)O_(2) on decomposition gives 10 volumes of oxygen at 1 atm and 273 K or 1 litre of H_(2)O_(2) gives 10 litre of O_(2) at 1 atm and 273 K The decomposition of H_(2)O_(2) is shown as under : H_(2)O_(2)(aq) to H_(2)O(l)+(1)/(2)O_(2)(g) H_(2)O_(2) can acts as oxidising as well as reducing agent. As oxidizing agent H_(2)O_(2) is converted into H_(2)O and as reducing agent H_(2)O_(2) is converted into O_(2) . For both cases its n-factor is 2. :. "Normality " "of" H_(2)O_(2) " solution " =2xx " molarity of" H_(2)O_(2) solution What is the molarity of "11.2 V" H_(2)O_(2) ?

A bottle of an aqueous H_2O_2 solution is labelled as '28 V' H_2O_2 and the density of the solution (in g/mL) is 1.25 . Choose the corrects option : A) Molality of H2O2 is 2 B) Molarity of H2O2 is 5 C) Molality of H2O2 is 2.15 D) None of these

Decomposition of H_2O_2 is prevented by

Decomposition of H_2O_2 follows a first order reaction. In fifty minutes the concentration of H_2O_2 decreases from 0.5 to 0.125 M in one such decomposition. When the concentration of H_2O_2 reaches 0.05 M, the rate of formation of O_2 will be

A 3.4g sample of H_(2)O_(2) solution containing x%H_(2)O by mass requires xmL of a KMnO_(4) solution for complete oxidation under acidic conditions. The normality of KMnO_(4) solution is :

Give one reaction to show that H_2O_2 is an acid.

Give one reaction to show that H_2O_2 is oxidising agent.