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How is pure H2O2obtained ?...

How is pure `H_2O_2`obtained ?

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The answer to each of the following questions is a single- digit -integer ranging from 0 to 9. Darken the correct digit. Acidified KMnO_4 oxidises H_2O_2 to H_2O and O_2 . The coefficient of H_2O_2 in the balanced chemical reaction of KMnO_4 with H_2O_2 in the presence of dil H_2SO_4 is

The answer to each of the following questions is a single- digit-integer ranging from 0 to 9. Darken the correct digit. Acidified KMnO_4 oxidises H_2O_2 to H_2O and O_2 . The coefficient of H_2O_2 in the balanced chemical reaction of KMnO_4 with H_2O_2 in the presence of dil H_2SO_4 is

What does a 20 volume H_2O_2 solution mean?

The strength of H_(2)O_(2) is expressed in several ways like molarity, normality,% (w/V), volume strength, etc. The strength of "10 V" means 1 volume of H_(2)O_(2) on decomposition gives 10 volumes of oxygen at 1 atm and 273 K or 1 litre of H_(2)O_(2) gives 10 litre of O_(2) at 1 atm and 273 K The decomposition of H_(2)O_(2) is shown as under : H_(2)O_(2)(aq) to H_(2)O(l)+(1)/(2)O_(2)(g) H_(2)O_(2) can acts as oxidising as well as reducing agent. As oxidizing agent H_(2)O_(2) is converted into H_(2)O and as reducing agent H_(2)O_(2) is converted into O_(2) . For both cases its n-factor is 2. :. "Normality " "of" H_(2)O_(2) " solution " =2xx " molarity of" H_(2)O_(2) solution What is the molarity of "11.2 V" H_(2)O_(2) ?