Calculate the ratio of electric and gravitational forces between two electrons. (charge of the electron (e)=`1.6xx10^(-19)` c, mass of electron (m)=`9.1x10^(-31)` kg , `1/(4piepsilon_0)= 9xx10^9 Nm^2C^(-2)`, universal gravitational constant `G=6.67xx10^(-11) Nm^2kg^(-2)`)

Explanation

The electric force `Fe=e^2/(4piepsilon_0r^2)`
The gravitational force `Fg=(Gm^2)/r^2`
`therefore (Fe)/(Fg)=1/(4piepsilon_0) xxe^2/(m^2G)=9xx10^9 xx (1.6xx10^(-19))^2/((9.1xx10^(-31))^2xx6.67xx10^(-11))=4.17xx10^42`