Home
Class 11
PHYSICS
Two particles of equal mass move in a ci...

Two particles of equal mass move in a circle of radius r under the action of their mutual gravitational attraction. Find the speed of each particle if its mass is m.

Text Solution

Verified by Experts


The particle will always remain diametrically opposite, so that the force on each particle will be directed along the radius.
When each particle is describing a circular orbit, the gravitational force on one of the particles must be equal to the necessary centripetal force.
`(mV^2)/r=(Gmm)/(2r)^2` i.e., `V=sqrt((Gm)/(4r))`
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    AAKASH SERIES|Exercise Exercise-I|124 Videos
  • GRAVITATION

    AAKASH SERIES|Exercise Exercise-II|78 Videos
  • GAUSS.S LAW

    AAKASH SERIES|Exercise PROBLEMS (LEVEL - II)|12 Videos
  • GRAVITATIONAL

    AAKASH SERIES|Exercise EXERCISE -3|154 Videos

Similar Questions

Explore conceptually related problems

Four particles , each of mass M and equidistant from each other, move along a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is:

Two particles each of mass m seperated by a distance d and move in a uniform circle under the action of their mutual force of attraction. The speed of each particle is