An artificial satellite is revolving in a circular orbit at a height of 1200km above the surface of the earth. If the radius of the earth is 6400km, mass is `6xx10^24` kg find the orbital velocity `(G=6.67xx10^(-11) Nm^2//kg^2)`

Explanation

`V_0=sqrt((GM)/(R+h))=sqrt(((6.67xx10^(-11))(6xx10^24))/((6400xx10^3)+(1200xx10^3)))`
`=sqrt((6.67xx10^(-11)xx6xx10^24)/(7600xx10^3))`=7.26 km/s