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A satellite is at a height of 25, 600km ...

A satellite is at a height of 25, 600km from the surface of the earth. If its orbital speed is 3.536km/s find its time period. (Radius of the earth = 6400km)

Text Solution

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R=6400 km = `6.4xx10^6` m , h=25
600= km =`25.6xx10^6`m , `v_0=3.536xx10^3` m/s
The time period `T=(2pi(R+h))/V_0=(2pi(25.6xx6.4)10^6)/(3.536xx10^3)`
`=(2pixx32)/3.536xx10^3`=56,870s
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