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The escape velocities on the surface of ...

The escape velocities on the surface of two planets of masses `m_1` and `m_2` and having the radius `r_1` and `r_2` are `v_1` and `v_2` respectively, then

A

`v_1/v_2=(m_1r_1)/(m_2r_2)`

B

`v_2/v_1=m_1/m_2 r_1/r_2`

C

`v_2/v_1=sqrt(m_2/m_1 r_1/r_2)`

D

`v_2/v_1=sqrt((m_1r_1)/(m_2r_2))`

Text Solution

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The correct Answer is:
C
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AAKASH SERIES-GRAVITATION-Practice Exercise
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  17. The mass of earth is 9 times of that of Mars. The radius of the earth ...

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