A particle of mass 2 kg is on a smooth horizontal table and moves in a circular path of radius 0.6m. The height of the table from the ground is 0.8 m. If the angular speed of the particle is 12 rad `s^(-1)` , the magnitude of its angular momentum about a point on the ground right under the centre of the circle is

Options

A. `11.52 kg m^(2)//s^(-1)`
B. `20.16 kg m^(2)s^(-1)`
C. `14.4 kg m^(2)s^(-1)`
D. `8.64 kg m^(2)s^(-1)`

Answer

C