A simple pendulum executing S.H.M in a s...

A simple pendulum executing S.H.M in a straight line has zero velocity at .a. and .b. whose distances from .o. in the same line OAB are .a. and .b.. If the velocity half -way between them is V then its time period is

`(pi(b+a))/v`

`pi(b-a)/v`

`(b+a)/(2v)`

`(b-a)/(2v)`

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