Radius of gyration of a disc of mass 5 kg about a transverse axis passing through its centre is 14.14 cm. Find its radius of gyration about its diameter and hence calculate its moment of inertia about its diameter

Explanation

Radius of gyration of a disc about a transverse axis passing through its centre
`K=sqrt((I)/(M))=sqrt((MR^(2))/(2M))=(R)/(sqrt2)=14.14cm`
`(,.I=(MR^(2))/(2))`
Radius of the dise, `R=14.14xxsqrt2=20cm`
Radius of gyration of the disc about its diameter.
`K=sqrt((I)/(M))=sqrt((MR^(2))/(4M))=(R)/(2)=(20)/(2)=10cm`
Moment of inertia about its diameter =
`(MR^(2))/(4)=(5(0.2)^(2))/(4)=5.00xx10^(-2)kgm^(2)`