Particles of masses 1 g, 2 g, 3 g, ... 100g, are kept at the marks 1 cm, 2 cm, 3 cm, ..... 100 cm respectively on a meter scale. Find the moment of inertia of the system of particles about a perpendicular bisector of the meter scale.

Explanation

`[1xx49^(2)+2xx48^(2)+3xx47^(2)+.........49xx1^(2)+52xx2^(2)+......98xx48^(2)+99xx49^(2)+100xx50^(2)]10^(-7)`
`=100p[50^(2)+49^(2)+48^(2)+.......+1^(2)]xx10^(-7)`
`=10^(-5)xx(1)/(6)xx50xx51xx101=0.431kgm^(2)`