A door of moment of inertia 4 kg `m^(2)` is at rest. When a torque of `2 pi Nm` acts on it find its angular acceleration. Find also its angular velocity after 1 s.

Explanation

`alpha=(tau)/(I)=(2pi)/(4)=(pi)/(2)rad//s^(2)`
`omega_(2)-omega_(1)=alphat" "omega_(2)=(pi)/(2)xx1`
`omega_(2)=1.57` rad/sec.