The moment of inertia of a flywheel making 300 revolutions per minute is 0.3 `kgm^2` . Find the torque required to bring it to rest in 20s.

Explanation

Torque `tau=Ialpha=I((omega_(2)-omega_(1)))/(t)`
`:.tau=(0.3xx(0-10pi))/(20)`
`=-0.15pi=-0.471Nm`