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For an ideal gas its adiabatic exponent ...

For an ideal gas its adiabatic exponent is `gamma` . In some process its molar heat capacity varies as `C = alpha/T`, where `alpha` is a constant. Work performed by one mole of gas during its heating from `T_0` to `nT_0` will be

A

`alpha log_e n`

B

`alpha log_e n - (n-1) RT_0`

C

`alpha log_e n - (n-1)/(gamma -1) RT_0`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C
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