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Two rods of same length and areas of cross-section `A_(1)` and `A_(2)` have their ends maintained at same temperature. If `K_(1)` and `K_(2)` are their thermal conductivities, `c_(1)` and `c_(2)` are the specific heats of their material and `rho_(1),rho_(2)` their densities, then for the rate of flow by conduction through them to be equal

A

`(A_(1))/(A_(2))=(K_(1))/(c_(1)rho_(1))(c_(2)rho_(2))/(K_(2))`

B

`(A_(1))/(A_(2))=(K_(1))/(K_(2))`

C

`(A_(1))/(A_(2))=(K_(1))/(K_(2))(c_(1)rho_(1))/(c_(2)rho_(2))`

D

`(A_(1))/(A_(2))=(K_(2))/(K_(1))`

Text Solution

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The correct Answer is:
D
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