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1.0 g of non - electrolyte solute dissol...

1.0 g of non - electrolyte solute dissolved in 50 g of benzene lowered the freezing point of benzene by 0.4 K. Find the molar mass of the solute. [Given : Freezing point depression constant of benzene = 5.12 K. kg mol].

Text Solution

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`DeltaT_(f)=0.40K`
`K_(f)="5.12 kg mol"^(-1)`
`W_(2)=1g`
`W_(1)="50.5 gm "=(50.5)/(1000)kg`
`M_(2)=(K_(f))/(DeltaT_(f))xx(W_(2))/(W_(1))`
`therefore" "M_(2)=(5.12)/(0.40)xx(1)/(50.5)xx1000`
`="2.56 g mol"^(-1)`
Thus, the molecule mass of the solute `=" 256 g mol"^(-1)`.
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