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In cold countries, ethylene glycol is ad...

In cold countries, ethylene glycol is added to water in the radiators of cars during winters. It results in :

A

Lowering boiling point

B

Reducing viscosity

C

Reducing specific heat

D

Lowering freezing point

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In cold countries …………is used as an anti-freezing agent in the radiator of car.

Why is it advised to add ethylene glycol to water in car radiator while driving in a hill station?

The boiling point elevation and freezing point depression of solutions have a number of partical applications. Ethylene glycol (CH_(2)OH-CH_(2)OH) is used in automobile radiatiors as an antifreeze because it lowers the freezing point of the coolant. The same substance also helps to prevent the radiator coolant from boiling away by elevating the boiling point. Ethylene glycol has low vapour pressure. We can also use glycerol as an antifreeze. In order for the boiling point elevation to occur, the solute must be non-volatile, but no such restriction applies to freezing point depression. For example, methanol (CH_(3)OH) , a fairly volatile liquid that boils only at 65^(@)C , is sometimes used as an antifreeze in automobile radiators. 620 g glycol is added to 4 kg water in the radiator of car. What amount of ice will separate out at -6^(@)C ?

Ethylene glycol is used as an antifreeze in a cold climate. Mass of ethylene glycol which should be added to 4 kg of water to prevent it from freezing at - 6^(@)C will be ( K for water = 1.86 "K kg mol"^(-1) , and molar mass of ethylene glycol = 62 g "mol"^(-1) )

A 0.5 molal solution of ethylene glycol in water is used as coolant in a car. If the freezing point constant of water be 1.86^(@)C per mol, the mixture will freeze at

a) 24 g of a non-volatile, non-electrolyte solute is added to 600 g of water. The boiling point of the resulting solution is 373.35K. Calculate the molar mass of the solute ("Given boiling point of pure water = 373 K and Kb for water=0.52 K kg mol"^(-1)) .

In a cold climate water gets frozen causing damage to radiator of a car. Ethylene glycol is used as an anifreezing agent. Calculate the amount of ethylene glycol to be added to 4 kg of water to prevent it from freezing at -6^(@) . ( K_(f) for water = 1.85 kg mol^(-1) )