An electric field is uniform and `E=200 hatiNC^(-1)` along `+x`s and `E=-200hatiNC^(-1)` along `-x` direction. A right circular cylinder of length 0.20 m and radius 0.05 m has its centre at the origin and its axis along the x-axis so that one face is `x=+0.10m` and the other `=x-0.10m`.
a. What is the net outward flux through each flat face?
b. What is the flux through the side of the cylinder?
c. What is the net outward flux throught the cylinder?
d. What is the net charge inside the cylinder?

Explanation

(a) we can see from the that on the left face E and `triangle S` are parallel therefore the outward flux is
(b) for any point on the side of the cylinder E is perpwendicular to `triangle S` and hence E `triangleS=0` therefore the flux out of the side of the cylinder is zero
(c ) net outward flux through the cylinder
`Phi =1.57 +1.57 +0=3.14 N m^(2) c^(-1)`

(d) the net charge within the cylinder can be found by using gauss.s law which gives
`q=epsilon_(0) Phi`
`=2.78 xx10^(-11) c`