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The digits of a three digit number N are...

The digits of a three digit number N are in A.P. If sum of the digit is 15 and the number obtained by re-versing the digits of the number is 594 less than the original number, then `(1000)/(N-252)` is equal to

A

`5//6`

B

`5//3`

C

`0.06`

D

`0.03`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will denote the three-digit number \( N \) as having digits \( a - d \), \( a \), and \( a + d \), where \( a \) is the middle digit and \( d \) is the common difference of the arithmetic progression (A.P.). ### Step 1: Set up the equations based on the problem statement 1. The digits are in A.P., so we can express them as: - Hundreds place: \( a + d \) - Tens place: \( a \) - Units place: \( a - d \) 2. The sum of the digits is given as 15: \[ (a + d) + a + (a - d) = 15 \] Simplifying this gives: \[ 3a = 15 \implies a = 5 \] ### Step 2: Find the value of \( d \) 3. Now, substituting \( a = 5 \) into the equation for the digits: \[ (5 + d) + 5 + (5 - d) = 15 \] This simplifies to: \[ 15 = 15 \quad \text{(which is always true)} \] 4. Next, we use the information that the number obtained by reversing the digits is 594 less than the original number: - Original number \( N = 100(5 + d) + 10(5) + (5 - d) \) - Reversed number \( R = 100(5 - d) + 10(5) + (5 + d) \) ### Step 3: Set up the equation for the difference 5. The equation for the difference between the original number and the reversed number is: \[ N - R = 594 \] Substituting for \( N \) and \( R \): \[ [100(5 + d) + 10(5) + (5 - d)] - [100(5 - d) + 10(5) + (5 + d)] = 594 \] ### Step 4: Simplify the equation 6. Simplifying the left side: \[ (500 + 100d + 50 + 5 - d) - (500 - 100d + 50 + 5 + d) = 594 \] This simplifies to: \[ (100d - d + 100d + d) = 594 \implies 198d = 594 \] ### Step 5: Solve for \( d \) 7. Dividing both sides by 198: \[ d = \frac{594}{198} = 3 \] ### Step 6: Find the digits of \( N \) 8. Now we can find the digits of \( N \): - Hundreds place: \( 5 + 3 = 8 \) - Tens place: \( 5 \) - Units place: \( 5 - 3 = 2 \) Thus, the number \( N \) is \( 852 \). ### Step 7: Calculate \( \frac{1000}{N - 252} \) 9. Now we need to calculate: \[ N - 252 = 852 - 252 = 600 \] Therefore: \[ \frac{1000}{600} = \frac{10}{6} = \frac{5}{3} \] ### Final Answer The value of \( \frac{1000}{N - 252} \) is \( \frac{5}{3} \).
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