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Sum to 25 terms of the series 0.5+0.55 +...

Sum to 25 terms of the series 0.5+0.55 +0.555+…is :

A

`(5)/(81)(224-10^(-25))`

B

`(5)/(9)(224-10^(-25))`

C

`(5)/(81)(224-10^(-24))`

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the sum of the first 25 terms of the series 0.5 + 0.55 + 0.555 + ..., we can follow these steps: ### Step 1: Identify the Pattern The series can be expressed as: - 0.5 = 5/10 - 0.55 = 55/100 = 5.5/10 - 0.555 = 555/1000 = 5.55/10 We can see that each term can be written as: \[ a_n = \frac{5}{10} + \frac{5}{100} + \frac{5}{1000} + ... \] ### Step 2: Factor Out the Common Term We can factor out 5 from the series: \[ S = 5 \left( \frac{1}{10} + \frac{11}{100} + \frac{111}{1000} + ... \right) \] ### Step 3: Rewrite the Series Notice that: - The first term is \( 0.1 \) - The second term is \( 0.11 \) - The third term is \( 0.111 \) This can be expressed as: \[ S = 5 \left( 0.1 + 0.11 + 0.111 + ... \right) \] ### Step 4: Express in Terms of a Geometric Series The series inside the parentheses can be rewritten as: \[ S = 5 \left( \frac{1}{10} + \frac{11}{100} + \frac{111}{1000} + ... \right) \] This can be simplified to: \[ S = 5 \left( \frac{1}{10} + \frac{1}{10} \cdot \frac{1}{10} + \frac{1}{10} \cdot \frac{1}{100} + ... \right) \] ### Step 5: Identify the Geometric Series The series \( 0.1, 0.11, 0.111, ... \) can be recognized as a geometric series with: - First term \( a = \frac{1}{10} \) - Common ratio \( r = \frac{1}{10} \) ### Step 6: Use the Formula for the Sum of a Geometric Series The sum of the first \( n \) terms of a geometric series is given by: \[ S_n = a \frac{1 - r^n}{1 - r} \] For our series: - \( n = 25 \) - \( a = \frac{1}{10} \) - \( r = \frac{1}{10} \) Thus, the sum becomes: \[ S_{25} = \frac{1/10 \cdot (1 - (1/10)^{25})}{1 - 1/10} \] \[ S_{25} = \frac{1/10 \cdot (1 - (1/10)^{25})}{9/10} \] \[ S_{25} = \frac{1 - (1/10)^{25}}{9} \] ### Step 7: Calculate the Total Sum Now, substituting back into the equation for \( S \): \[ S = 5 \cdot S_{25} = 5 \cdot \frac{1 - (1/10)^{25}}{9} \] \[ S = \frac{5(1 - (1/10)^{25})}{9} \] ### Step 8: Final Calculation Now we can calculate the final value: \[ S = \frac{5(1 - 10^{-25})}{9} \]
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MCGROW HILL PUBLICATION-PROGRESSIONS-Questions from Previous Years. B-Architecture Entrance Examination Papers
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