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Let Sn denote the sum of the cubes of th...

Let `S_n` denote the sum of the cubes of the first `n` natural numbers and `s_n` denote the sum of the first `n` natural numbers. Then `sum_(r=1)^n S_r/s_r` is equal to

A

`(1)/(2)n(n+1)`

B

`(1)/(2) (n+1) (n+2)`

C

`(1)/(6)n(n+1)(n+2)`

D

`(1)/(4)n^(2)(n+1)^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
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