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The sum of 10 terms of the series sqrt2 ...

The sum of 10 terms of the series `sqrt2 + sqrt6 + sqrt18 +...` is

A

`121 (sqrt(6)+sqrt(2))`

B

`(121)/(2) (sqrt(3)+1)`

C

`243 (sqrt(3)+1)`

D

`243 (sqrt(3)-1)`

Text Solution

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The correct Answer is:
A
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