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The sum of n terms of the series 1^2+2.2...

The sum of `n` terms of the series `1^2+2.2^2+3^2+2.4^2+5^2+2.6^2+....` is`(n(n+1)^2)/2` when n is even . when n is odd , the sum is

A

`1/4n(n+1)^2`

B

`1/2n^2(n+1)`

C

`3/2n(n+1)`

D

`1/4n^2(n+1)^2`

Text Solution

Verified by Experts

The correct Answer is:
B
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