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where f (n) = [(1)/(3) + (3n)/(100)] n, ...

where f (n) = `[(1)/(3) + (3n)/(100)]` n, where [ n] denotes the greatest integer less than or equal to n. Then `sum_(n=1)^(56)int (n)` is equal to :

A

56

B

689

C

1287

D

1399

Text Solution

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The correct Answer is:
D
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